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So... The maximum kinetic energy of photoelectrons ejected from a tungsten surface by monochromatic light of wavelength 248nm was fround to be 8.6*10^-20. Find the work function of tungsten? Planck constant = 6.6*10^-34 Js Speed of light = 300,000,000ms-1 Electronic charge = -1.6*10^-19 C Its Physics...

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dont you think thats a bit difficult to work out?

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"iluvmrmen" wrote:

dont you think thats a bit difficult to work out?

Its only AS level. It isn't crazy university Physics. it was posted mainly as a joke due to the claim of being an "expert in science"...

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i need help with atoms

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What part about them?

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"Mahatama" wrote:

So... The maximum kinetic energy of photoelectrons ejected from a tungsten surface by monochromatic light of wavelength 248nm was fround to be 8.6*10^-20. Find the work function of tungsten? Planck constant = 6.6*10^-34 Js Speed of light = 300,000,000ms-1 Electronic charge = -1.6*10^-19 C Its Physics...

E= φ - KE ∴ φ= KE + E c= λf ∴ f= c/λ E=hf ∴ E = h * c/λ E= KE + h * c/λ Substituting values for 〖KE〗_e = 8.6*10^-20 J, c = 3.00 * 10 ^ 8 m/s, h = 6.63 * 10 ^ -34 J∙s, and λ = 2.48 * 10 ^ 7 m, you should get the result of 8.9 * 10 ^ -19 J, or 5.6 eV, a 24.4% error from the established work function of tungsten, 4.5 eV.

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"Eddward28" wrote:

"Mahatama" wrote:

So... The maximum kinetic energy of photoelectrons ejected from a tungsten surface by monochromatic light of wavelength 248nm was fround to be 8.6*10^-20. Find the work function of tungsten? Planck constant = 6.6*10^-34 Js Speed of light = 300,000,000ms-1 Electronic charge = -1.6*10^-19 C Its Physics...

E= φ - KE ∴ φ= KE + E c= λf ∴ f= c/λ E=hf ∴ E = h * c/λ E= KE + h * c/λ Substituting values for 〖KE〗_e = 8.6*10^-20 J, c = 3.00 * 10 ^ 8 m/s, h = 6.63 * 10 ^ -34 J∙s, and λ = 2.48 * 10 ^ 7 m, you should get the result of 8.9 * 10 ^ -19 J, or 5.6 eV, a 24.4% error from the established work function of tungsten, 4.5 eV.

Wow. Considering you're only 12 you're very smart.

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